DIT | Easy way for Supernetting IPV4 in Computer Networking


3.1   # UNDERSTAND AND EXPLAINED OF SUPERNETTING WITH EXAMPLE

Supernetting, also known as classless inter-domain routing (CIDR), is a method used in IP networking to aggregate multiple contiguous IP address ranges into a single, larger address block. This helps optimize routing tables and improves the efficiency of IP address allocation. In supernetting, a network administrator can combine several smaller subnets into a single supernet, which reduces the number of entries in routing tables and minimizes the overhead on routers. For example, instead of announcing several /24 networks, a single /22 supernet can be used to represent those networks. This approach is especially useful in conserving IP addresses and managing network routing more effectively, particularly as the Internet continues to grow.

PROPERTIES :

o Number of network unlimited on it.
o Number of IP limited on it.
o Its barrow from Left hand side.


PRACTICAL :

Network number: 200.10.20.20
Number of subnet required is 5 and subnet =?

Solution  

NETWORK 200 10 20 20
SUBNET MASK 255 255 255 0
Convert to binary
NETWORK 11001000 00001010 00010100 00010100
SUBNET MASK 11001000 00001010 00010100 00010100
=============================================
And Operation 11001000 00001010 00010100 00000000
Network Address 200 10 20 0
Therefore, 2n – 2 = 5
=> 2 range to power 1 – 2 = 0 (False)
=> 2 range to power 2 – 2 = 2 (False)
=> 2 range to power 3 – 2 = 6 > 5 (True)
=> n = 3 (Number of 0s to be changed into 1s =3)
SUBNET MASK 255 255 255 0

Convert to binary                                                                                                                 3 bits enable

SUBNET MASK 11111111 11111111 11111111 11100000
Solve the Subnet mask
SUBNET MASK 255 224 255 0

=> Magic number = 256 – Mask => 256 -224 = 32

Subnet 0 200 10 20 0/27
Subnet 1 200 10 20 32/27
Subnet 2 200 10 20 64/27
Subnet 3 200 10 20 96/27
Subnet 4 200 10 20 128/27
Subnet 5 200 10 20 160/27
Subnet 6 200 10 20 192/27
Subnet 7 200 10 20 224/27
Therefore,
You will find Broadcast domain 31; Host 1-30 from subnet 0
Broadcast domain 63; Host 33 - 62 from subnet 1
Broadcast domain 95; Host 65 - 94 from subnet 2
Broadcast domain 127; Host 97 - 126 from subnet 3
Broadcast domain 159; Host129 - 158 from subnet 4
Broadcast domain 191; Host 161 - 190 from subnet 5
Broadcast domain 223; Host 193 - 222 from subnet 6




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